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Robert Jordan's Blog XECryption
Luthien's Cryptographic Challenge
Welcome

Welcome to Luth's TSOS Cryptographic Challenge Episode 2!

This old Italian challenge is presented a bit different than the last. Maybe it will last longer? Maybe not. We'll see.

To the actual content, below is an encrypted quotation. Decrypt it! Emailing me (see help duties) is how you should submit your solutions.

76 53 41 35 121 53 41 54 100 79 41 43 35 94 103 121 49 121 53 103 35 68 49 35 41 43 42
34 94 94 121 34 43 35 41 64 35 100 70 79 41 42 63 94 103 49 54 42 41 121 41 63
52 41 121 41 42 70 103 35 41 121 64 34 35 41 64 35 100 70 79 41 42 49 94 103 117 117 41 42 41 35 121
38 36 121 53 43 121 34 35 41 52 121 53 103 49 117 41 43 121
76 103 107 107 79 41 51 41 98 121 43 49 43 42 100 107 41
71 53 41 103 42 98 42 34 94 100 54 121 43 107 64 43 36 49 41 69 100 43 107 63 121 53 41 49 43 70 41 63
71 34 121 53 41 54 100 79 41 34 117 43 121 53 103 42 94
50 117 121 53 41 35 100 70 79 41 42 34 117 121 53 103 35 68 49 35 43 70 41 94 84
71 53 41 35 63 68 41 35 41 42 43 107 107 36 49 98 41 43 51 103 35 68 63
71 53 41 42 41 70 43 103 35 103 35 68 43 70 34 100 35 121
50 117 121 53 41 54 100 79 41 42 34 34 121 49 49 100 79 121 42 43 54 121 41 94
76 103 107 107 79 41 36 34 100 42 94 41 49 103 42 41 94 54 34 100 35 121 84

Good Luck!

RULES
  1. Every week I will post 1 hint to help solve the challenge.
  2. The reward lessens with every hint posted.
  3. No hints will be given outside of what is posted here. So don't even ask.
HINTS
  1. Week 0 hint: See above, it's Italian!
  2. Week 1 hint: My algorithm is a convex regular polygon.
  3. Week 2 hint: you can probably take the x2 and build a character map, but what happens if you instead realize that the results are %127 and you then work backwards realizing that we have remainders from the list of square numbers?

Extra credit: recover the particular algorithm I used and send that to me too. =-)
Extra credit 2: what's the context I took this from?
 

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